Elmann Creaive Corner film into musical Ruth and Esther

Abbreviations of Titles of books of the bible. Using Heat Colours and Temperatures Light Yellow 1975 Degree Farh. , Yellow 1828 Degree Farh., Orange 1725 Degree Farh., Bright Red Degree Red. Colour according to System of  Rain Bow. OA = 16 Red Light and using 41 Degrees into 0.71545 x 1.34 = 0.958703/ 2 Degrees = 0.0349 = 27.47 +- Coefficient Music 11.47 = 16. Also 11.47 x 2 = 22.94 = Coeficient = 126.17 + 73.9815 = 200.1515 usu follows. Musical Insruments. In every musical instrument depending on strings or wires to give the notes you will see screws or other devices provided for tuning purposes. The precise notes wanted can be got by regulating the tensions with these screws. Strings for the very high notes are made of thin and very dtrong material. Being thin the weight per unit of length is small and so the tension needed is not excessive. A thick wire would have to be tightened up so enormously thatthere would be some danger of buckling the musical instrument, nd tha would put all the other strings out of tune. Strings for the low notes are made of thick heavy material because the energy in a thin string vibrating with low frequency would be too small to make a loud enough sound. Vibrating at high frequency, thin string will possess plenty of energy. You mut remember that, for a given amplitude of vibration, the energy in a vibrating string is proportional to the force needed to deflect it at the start of its vibrations. Plainly this force is greatest when the tension is greatest. By making all the strings of such lengths and thicknesses that the tension in them can be the same, instrument makers ensure that they will vibrate with equal energy. In the violin, a complicating factor is that the strings must all be of equal length. Strings of equal length, stretched to equal tension, are required to vibrate with frequencies of 100 and 200 respectively. If the string for the latter frequency weights 1 lb.for each 100-length, what must be the weight per 100-ft. length of the string for the frequency of 100? As the strings are of equal length, the two wavelengths will also be equal, and so the difference in frequency must be occasionned by a diffirence between the velocity v100 of wave propagation in the thick string and the corresponding velocity v200 in the thin string. As the two tensions are equal:

v100/v200 = root of 200/w100 = 100/200, where w200 is given as 0.0, and w 100 is the weight we have to calculate w200/w100 = (100/200) 2 = 1/4. Hence w100 = 4 x w200 = 4 x 0.01 = 0.4 lb. Consequently, the weight of 100 ft. of this material will be 100 x 0.04 = 4 lb.